Shubham sells two articles first on 20% loss and 2nd on 60% profit. Find their selling price of the article which is sold at 60% profit if the difference of their cost price is ₹3200 and the selling price of both the articles is same.

₹5120

Let the CP of two articles is x (which is sold at 20% loss) and y (which is sold at 60% profit)

ATQ, SP of both are same;

⇒ x × 80% = y × 160%

⇒ x  = 2y

⇒ x : y = 2 : 1

Here,

⇒ y - x = 3200

⇒ 2R - 1R = 3200

⇒ 1R = 3200

⇒ CP₁ (y) = 3200 and CP₂ (x) = 6400 

⇒ SP (at 60% profit) = 3200 × \(\frac{160}{100}\) = 5120