If two coins are tossed five times, then the probability of getting 5 heads and 5 tails is

$\frac{63}{256}$ $\frac{1}{1024}$ $\frac{2}{205}$ $\frac{9}{64}$

$\frac{63}{256}$

Required probability $= {^{10}C}_5 \left(\frac{1}{2}\right)^5\left(\frac{1}{2}\right)^5 =\frac{63}{256}$