If $\int f(x)dx=-\cos\sqrt{x}+c$, then f(x) =
Answer & explanation
Correct answer: option 4
$\int f(x)dx=-\cos\sqrt{x}+c$ so differentiate on both sides wrt x
$f(x)=\frac{\sin \sqrt{x}}{2\sqrt{x}}$
If $\int f(x)dx=-\cos\sqrt{x}+c$, then f(x) =
Correct answer: option 4
$\int f(x)dx=-\cos\sqrt{x}+c$ so differentiate on both sides wrt x
$f(x)=\frac{\sin \sqrt{x}}{2\sqrt{x}}$