A die is tossed four times. The probability of getting an odd number at least once, is
Answer & explanation
Correct answer: option 4
Probability of getting an odd number in a single throw of a die = $\frac{3}{6}=\frac{1}{2}$
Similarly, probability of getting an even number = $\frac{3}{6}=\frac{1}{2}$
as there are 6 outcomes → 1, 2, 3, 4, 5, 6
Probability of getting an even number four times = $\frac{1}{2}×\frac{1}{2}×\frac{1}{2}×\frac{1}{2}=\frac{1}{16}$
∴ Probability of getting an odd number at least once
=1− Probability of getting an even number four times
$1-\frac{1}{16}=\frac{16-1}{16}=\frac{15}{16}$
Option 4 is correct.