Shyam bought a car in 2023 worth ₹7 lakh. He made a down payment of ₹2.5 lakh and took a loan for the rest of the amount at the rate 12% p.a. for four years. The monthly EMI paid by Shyam in: (given (1.01)48 = 1.6122) |
₹ 9,000 ₹ 10,000.75 ₹ 11,850.75 ₹ 12,200.75 |
₹ 11,850.75 |
The correct answer is Option (3) → ₹ 11,850.75 $\text{Cost} = 700000,\;\; \text{Down payment} = 250000$ $\text{Loan} = 450000$ $r = 12\% \Rightarrow \text{monthly rate} = \frac{12}{12} = 1\% = 0.01$ $n = 4 \times 12 = 48$ $\text{EMI} = \frac{P r (1+r)^n}{(1+r)^n - 1}$ $= \frac{450000 \cdot 0.01 \cdot 1.6122}{1.6122 - 1}$ $= \frac{4500 \cdot 1.6122}{0.6122}$ $= \frac{7254.9}{0.6122} \approx 11860$ The monthly EMI is approximately ₹11,860. |