The inverse saturation current in a P-N junction diode at 27°C is $10^{−5}$ ampere. The value of forward current at 0.2 volt will be:
Answer & explanation
Correct answer: option 3
$I_f=I_s[e^{\frac{qV}{kt}}-1]$
$=10^{-5}×[exp.(\frac{1.6×10^{-19}×0.2}{1.4×10^{-23}×300})-1]$
$=10^{-5}×[2038.6 − 1]=20.376×10^{−3}A$