Practicing Success
The inverse saturation current in a P-N junction diode at 27°C is $10^{−5}$ ampere. The value of forward current at 0.2 volt will be: |
$2037.6 × 10^{−3}A$ $203.76 × 10^{−3}A$ $20.376 × 10^{−3}A$ $2.0376 × 10^{−3}A$ |
$20.376 × 10^{−3}A$ |
$I_f=I_s[e^{\frac{qV}{kt}}-1]$ $=10^{-5}×[exp.(\frac{1.6×10^{-19}×0.2}{1.4×10^{-23}×300})-1]$ $=10^{-5}×[2038.6 − 1]=20.376×10^{−3}A$ |