If $A=\begin{bmatrix}1&0&0\\0&-1&0\\0&0&1\end{bmatrix}$, then $A^{-1}$ is equal to |
$\begin{bmatrix}-1&0&0\\0&1&0\\0&0&-1\end{bmatrix}$ $\begin{bmatrix}-1&0&0\\0&1&0\\0&0&1\end{bmatrix}$ $\begin{bmatrix}1&0&0\\0&-1&0\\0&0&-1\end{bmatrix}$ $\begin{bmatrix}1&0&0\\0&-1&0\\0&0&1\end{bmatrix}$ |
$\begin{bmatrix}1&0&0\\0&-1&0\\0&0&1\end{bmatrix}$ |
The correct answer is Option (4) → $\begin{bmatrix}1&0&0\\0&-1&0\\0&0&1\end{bmatrix}$ $A=\begin{pmatrix}1&0&0\\0&-1&0\\0&0&1\end{pmatrix}$ $A$ is a diagonal matrix, so $A^{-1}$ is obtained by taking reciprocals of the diagonal entries. $A^{-1}=\begin{pmatrix}1&0&0\\0&-1&0\\0&0&1\end{pmatrix}$ Final answer: $A^{-1}=A$ |