Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

A student gets 177 marks yet fails by 55 marks. If the passing mark is 29%, then what is the maximum mark?

Options:

900

750

700

800

Correct Answer:

800

Explanation:

Total marks required to pass = 177 + 55 = 232

Passing Percentage = 29%

Therefore,

29% of Maximum Marks = 232

Maximum Marks = \(\frac{232}{29}\) × 100 = 800