Practicing Success
The difference between two numbers is 15 and their HCF and LCM are 3 and 108 respectively. Find the difference between their reciprocals. |
$\frac{5}{54}$ $\frac{5}{108}$ $\frac{5}{81}$ $\frac{5}{112}$ |
$\frac{5}{108}$ |
Let the two numbers are x and y ⇒ x – y = 15 and xy = 3 × 108 [Product of two number = HCF × LCM] ⇒ \(\frac{1}{y}\) – \(\frac{1}{x}\) ⇒ \(\frac{x - y}{xy}\) ⇒ \(\frac{15}{3 × 108}\) ⇒ \(\frac{5}{108}\) |