Match List I with List II
| LIST I | LIST II |
| A. Invert sugar | I. \(\alpha \)-D-glucose and \(\alpha \)-D-glucose |
| B. Maltose | II. \(\beta \)-D-galactose and \(\beta \)-D-glucose |
| C. Lactose | III. branched chain polymer of \(\alpha \)-D-glucose unit |
| D. Amylopectin | IV. Hydrolysis of sucrose |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → A-IV, B-I, C-II, D-III
Disaccharides give two monosaccharide units on hydrolysis; polysaccharides are long chains of monosaccharide units joined by glycosidic linkages.
(A) Invert sugar — This matches (IV) Hydrolysis of sucrose. Sucrose (dextrorotatory) is hydrolysed to an equimolar mixture of D-(+)-glucose and D-(−)-fructose; fructose rotates more strongly to the left, so the sign of rotation changes and the product is called invert sugar.
\( \displaystyle \ce{C12H22O11 + H2O} \xrightarrow{\ce{H+}} \ce{C6H12O6 + C6H12O6} \)
(B) Maltose — This matches (I) \(\alpha \)-D-glucose and \(\alpha \)-D-glucose. Maltose is made of two α-D-glucose units linked between C1 of one and C4 of the other.
(C) Lactose — This matches (II) \(\beta \)-D-galactose and \(\beta \)-D-glucose. Lactose (milk sugar) is made of β-D-galactose and β-D-glucose, linked between C1 of galactose and C4 of glucose.
(D) Amylopectin — This matches (III) branched chain polymer of \(\alpha \)-D-glucose unit. Amylopectin (80–85% of starch) is a branched chain of α-D-glucose units: C1–C4 links in the chain and C1–C6 links at the branches.
NCERT (2026-27 edition):
Disaccharides – …
