CUET Preparation Today
$\int\limits_{-1}^1 \sin ^{11} x d x=$ |
$\frac{10 . 8 . 6 . 4 . 2}{11 . 9 . 7 . 5 . 3}$ $\frac{10 . 8 . 6 . 4 . 2}{11 . 9 . 7 . 5 . 3} \frac{\pi}{2}$ 1 0 |
0 |
sin11x is odd function of x. So, integral is zero. Hence (4) is the correct answer. |
