Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If sin θ + cos θ = x; what is the value of sinθ.cosθ ?

Options:

\(\frac{1}{2}\)(x2 -  \(\frac{1}{x^2}\))

\(\frac{1}{4}\)(x2 -  \(\frac{1}{x^2}\))

1

0

Correct Answer:

\(\frac{1}{4}\)(x2 -  \(\frac{1}{x^2}\))

Explanation:

sin θ + cos θ = x

⇒sin θ - cos θ = \(\frac{1}{x}\)

4sinθ.cosθ = (sinθ + cosθ)2 - (sinθ - cosθ)2

⇒ 4sinθ.cosθ = x2 - \(\frac{1}{x^2}\)

⇒ sinθ.cosθ = \(\frac{1}{4}\)(x2 -  \(\frac{1}{x^2}\))