Practicing Success
If sin θ + cos θ = x; what is the value of sinθ.cosθ ? |
\(\frac{1}{2}\)(x2 - \(\frac{1}{x^2}\)) \(\frac{1}{4}\)(x2 - \(\frac{1}{x^2}\)) 1 0 |
\(\frac{1}{4}\)(x2 - \(\frac{1}{x^2}\)) |
sin θ + cos θ = x ⇒sin θ - cos θ = \(\frac{1}{x}\) 4sinθ.cosθ = (sinθ + cosθ)2 - (sinθ - cosθ)2 ⇒ 4sinθ.cosθ = x2 - \(\frac{1}{x^2}\) ⇒ sinθ.cosθ = \(\frac{1}{4}\)(x2 - \(\frac{1}{x^2}\)) |