Rte constant 'k' for a certain reaction is \(k = 2.3 × 10^{−5}\) L mol−1 s−1. Order of the reaction is:
Answer & explanation
Correct answer: option 3
Rate of the reaction is given by,
Rate=k × [A]x, where x is the order of reaction
\(\left(\frac{mol}{L}\right)^2 = 2.3 × 10^{−5}L (mol^{−1})(s^{−1})[A]^x\)
\(\left(\frac{mol}{L}\right)^2 = \text{ constant } (s^{−1})\left(\frac{mol}{L}\right)^x\)
Therefore, x=2 and the reaction is second order