Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Question:

The sum of two numbers is 36 and their HCF is 4. How many pairs of such numbers are possible ?

Options:

3

4

2

1

Correct Answer:

3

Explanation:

Let, the numbers are 4x and 4y

ATQ,

⇒ 4x + 4y = 36

⇒ 4(x + y) = 36

⇒ x + y = 9

⇒ (1, 8)

⇒ (2, 7)

⇒ (4, 5)

We can see the 3 possible pairs.