The revenue function is given by \( R(x)=150x-2x^2-x^3 \), where \( x \) is the number of units demanded, then the marginal revenue when 5 units are sold, is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Rs. 55
Marginal revenue is the derivative of the revenue function:
\( \displaystyle MR=R'(x)=150-4x-3x^2 \)
\( \displaystyle R'(5)=150-20-75=55 \)
The marginal revenue when 5 units are sold is Rs. 55.
NCERT (2026-27 edition):
Rate of Change of Quantities
