If $x + y + z = 5, \frac{1}{x}+\frac{1}{y}+\frac{1}{z} = 0, xyz = 12$ and $x^3 + y^3 + z^3 = 151,$ then the value of $(x^2 + y^2 = z^2)$ is :
Answer & explanation
Correct answer: option 2
A detailed explanation for this question is coming soon.
If $x + y + z = 5, \frac{1}{x}+\frac{1}{y}+\frac{1}{z} = 0, xyz = 12$ and $x^3 + y^3 + z^3 = 151,$ then the value of $(x^2 + y^2 = z^2)$ is :
Correct answer: option 2
A detailed explanation for this question is coming soon.