If (sinθ + cosθ) = \(\sqrt { 2}\) ; 0 < θ < 90°, then value of θ is:
Answer & explanation
Correct answer: option 2
Out of all options when θ = 45° ;
sinθ + cosθ = \(\frac{1}{√2}\) + \(\frac{1}{√2}\) = \(\sqrt { 2}\) satisfies equation
Hence,
θ = 45°
If (sinθ + cosθ) = \(\sqrt { 2}\) ; 0 < θ < 90°, then value of θ is:
Correct answer: option 2
Out of all options when θ = 45° ;
sinθ + cosθ = \(\frac{1}{√2}\) + \(\frac{1}{√2}\) = \(\sqrt { 2}\) satisfies equation
Hence,
θ = 45°