Match List I with List II

List I	List II
(A)	(I)
(B)	(II)
(C)	(III)
(D)	(IV)

Choose the correct answer from the options given below:

A-IV, B-I, C-III, D-II

The correct answer is option 2. A-IV, B-I, C-III, D-II.

A. We know that the reaction of phenol and water with bromine is known as bromination of phenol. Solvent has a great influence on the reaction. In different solvents, different products are obtained.

The bromination of phenol is a substitution reaction. Where the bromine replaces hydrogen present in the benzene ring of phenol. In the water solvent when phenol treated with \(Br_2\) gives a polybromo derivative in which all hydrogen atoms at ortho, meta, and para positions with respect to the \(−OH\) group are replaced by bromine atoms. It is so because in aqueous medium phenol ionizes to form peroxide ion. Due to the presence of negative ions, the ring gets highly activated and tri substitution occurs and the formation of 2,4,6 – tribromophenol takes place.

B. Phenol first reacts with concentrated sulphuric acid which converts it to phenol-2,4-disulphonic acid and then with concentrated nitric acid to get 2,4,6-Trinitrophenol. It is because \(-OH\) is a strong activating group toward electrophilic substitution. So it forms 2,4,6-Trinitrophenol instead of ortho or para nitro phenols.

C. The reaction of phenol with bromine is known as bromination of phenol. Solvent has a great influence on the reaction. In different solvents, different products are obtained.

Reaction with bromine in \(CS_2\): Phenol reacts with bromine in the presence of Carbon disulphide to form a mixture of o-bromophenol and p-bromophenol. 

D. Phenol reacts with dilute \(HNO_3\) at normal temperature to form mixture of ortho and para nitrophenol.