The current flowing through an inductor of self inductance L is continuously increasing. The correct graph, showing the variation of induced emf(e) versus $\frac{dI}{dt}$?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1)
Induced emf, $e=\frac{d\phi}{dt}=-\frac{d}{dt}(LI)$
$⇒e=-L\frac{dI}{dt}$