The current flowing through an inductor of self inductance L is continuously increasing. The correct graph, showing the variation of induced emf(e) versus $\frac{dI}{dt}$? |
The correct answer is Option (1) Induced emf, $e=\frac{d\phi}{dt}=-\frac{d}{dt}(LI)$ $⇒e=-L\frac{dI}{dt}$ |