In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is |
$\frac{1}{10}$ $(\frac{9}{10})^5$ $(\frac{1}{2})^5$ $\frac{9}{10}$ |
$(\frac{9}{10})^5$ |
The correct answer is Option (2) → $(\frac{9}{10})^5$ Total bulbs $=100$ Defective bulbs $=10$ Good bulbs $=90$ Probability that one bulb is good $=\frac{90}{100}=\frac{9}{10}$ Probability that all $5$ bulbs are good $=\left(\frac{9}{10}\right)^5$ The required probability is $\left(\frac{9}{10}\right)^5$. |