A person has to cover a distance of 91 km. If he increases his speed by 6 km/hr he reaches 6 hour early. Find his initial speed (in km/hr).
Answer & explanation
Correct answer: option 2
Let the initial speed = x km/hr
ATQ,
\(\frac{91}{x}-\frac{91}{x+6}=6\)
let x = 7 (by using option)
\(\frac{91}{7}-\frac{91 }{13}=6\)
13 – 7 = 6 (satisfied)
so, x = 7