Practicing Success
If $8x^3 + 27y^3 +64z^3 = 72 xyz$, then the relation between x, y and z can be : |
2x + 3y = -4z 2x + y + z = 0 2x - 3y + 4z = 0 2x + 3y = 4z |
2x + 3y = -4z |
Given that, 8x3 + 27y3 + 64z3 = 72 xyz, a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca) and if a + b + c = 0 than, a3+b3+c3=3abc (2x)3+(3y)3+(4z)3 = 3(2x)(3y)(4z) = 72xyz So it is satisfying the condition a3+b3+c3=3abc so, a = 2x , b = 3y ,c = 4z and a + b + c = 0 2x + 3y + 4z = 0 We can write this also as = 2x + 3y = -4z |