If increasing 60 by x% gives the same result as decreasing 100 by x%, then x% of 320 is what percent less than (x + 50)% of 160?

33\(\frac{1}{3}\)%

60 (100 + x)% = 100 (100 - x)%

     3 (100 + x) = 5 (100 - x)

 300 + 3x = 500 - 5x

           8x = 200

             x = 25

⇒ x% of 320  =  25% × 320  = 80

⇒ (x+50)% of 160 =(25+50)% × 160 = 75% of 160 = 120

 Difference 120 - 80 = 40

Percent less = \(\frac{40}{120}\) × 100 = 33\(\frac{1}{3}\)%