Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

A charge - Q is uniformly distributed over a non-conducting semicircular rod of radius R. The potential at the centre is:

Options:

0

$\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{R}$

$\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{2R}$

$\frac{1}{4 \pi \varepsilon_0} . \frac{2Q}{R}$

Correct Answer:

$\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{R}$

Explanation:

Potential at 0 due to elemental charge

$dq=\frac{1}{4 \pi \varepsilon_0} . \frac{dq}{R}$

Total Potential at 0 = $\frac{1}{4 \pi \varepsilon_0} \int\limits_0^{-Q} dq$

$= -\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{R}$