Practicing Success
A charge - Q is uniformly distributed over a non-conducting semicircular rod of radius R. The potential at the centre is: |
0 $\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{R}$ $\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{2R}$ $\frac{1}{4 \pi \varepsilon_0} . \frac{2Q}{R}$ |
$\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{R}$ |
Potential at 0 due to elemental charge $dq=\frac{1}{4 \pi \varepsilon_0} . \frac{dq}{R}$ Total Potential at 0 = $\frac{1}{4 \pi \varepsilon_0} \int\limits_0^{-Q} dq$ $= -\frac{1}{4 \pi \varepsilon_0} . \frac{Q}{R}$ |