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If $f : A \to B$ and $g : B \to C$ be the bijective functions, then $(g of)^{-1}$ is |
$f^{-1} og^{-1}$ $f og$ $g^{-1} of^{-1}$ $g of$ |
$f^{-1} og^{-1}$ |
The correct answer is Option (1) → $f^{-1} og^{-1}$ ## Given that, $f : A \to B$ and $g : B \to C$ be the bijective functions. $(g of)^{-1} = f^{-1} og^{-1}$ |
