In a survey it was found that in a constituency, 55% of voters are male and the rest are female. 40% of the male voters are literate and $33\frac{1}{3}$ % of the female voters are illiterate. What percentage of the voters are literate?

52%

40% =\(\frac{2}{5}\) & 33\(\frac{1}{3}\) % = \(\frac{1}{3}\)

Total number of voters = 100x

Number of male voters = 55% of 100x = 55x

Number of Female voters = 100x - 55x = 45x

Literate Male = \(\frac{2}{5}\) × 55x = 22x

illiterate female = \(\frac{1}{3}\) × 45x = 15x

Literate female = 45x - 15x = 30x

Total Literate population = 30x + 22x = 52x

Percentage of literate population = \(\frac{52x}{100x}\)  × 100 = 52%