If OACB is a parallelogram with $\vec{OC} = \vec a$ and $\vec{AC} = \vec b$, then $\vec{OA} =$
Answer & explanation
Correct answer: option 2
In ΔOAC, we have
$\vec{OA}+\vec{AC}=\vec{OC}⇒ \vec{OA}+\vec b=\vec a⇒\vec{OA}=\vec a-\vec b$
If OACB is a parallelogram with $\vec{OC} = \vec a$ and $\vec{AC} = \vec b$, then $\vec{OA} =$
Correct answer: option 2
In ΔOAC, we have
$\vec{OA}+\vec{AC}=\vec{OC}⇒ \vec{OA}+\vec b=\vec a⇒\vec{OA}=\vec a-\vec b$