Practicing Success
What is the total energy of electron in the nth stationary orbit of hydrogen atom? |
$\frac{13.6}{n^2}J$ $\frac{-13.6}{n^2}eV$ $0.53n^2J$ $\frac{0.53}{n^2}eV$ |
$\frac{-13.6}{n^2}eV$ |
The correct answer is Option (2) → $\frac{-13.6}{n^2}eV$ |