Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

In a plane electromagnetic wave, the magnetic field oscillates sinusoidally at a frequency of $2.0×10^{10} Hz$ and amplitude $1.6×10^{-7}T$. The amplitude of the oscillating electric field is:

Options:

$5.3 × 10^{-16} Vm^{-1}$

$4.8 × 10^{-7} Vm^{-1}$

$4.8Vm^{-1}$

$48Vm^{-1}$

Correct Answer:

$48Vm^{-1}$

Explanation:

The correct answer is Option (4) → $48Vm^{-1}$

The relationship between $\vec E_0$ and $\vec B_0$ is,

$E_0=CB_0$

$E_0=(3×10^8)×(1.6×10^{-7})$

$=48Vm^{-1}$