CUET Preparation Today
The area of a triangle whose vertices are (-3, 0), (3, 0) and (0, k) is 6 . Then the value (or the values) of k will be: |
2, -2 2 -2 1 |
2, -2 |
The correct answer is Option (1) → 2, -2 Area $|Δ|=6$ so $Δ=±6$ or $\frac{1}{2}\begin{vmatrix}-3&0&1\\3&0&1\\0&k&1\end{vmatrix}=±6$ $≡\frac{k}{2}(6)=±6⇒k=±2$ or $k=2,-2$ |
