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The domain of function $f(x)=\frac{\sqrt{4-x^2}}{\sin^{-1}|x|}$ is |
[–1, 1] [–2, 2] [-1, 0) ∪ (0, 1] [-2, 0) ∪ (0, 2] |
[-1, 0) ∪ (0, 1] |
$f(x)=\frac{\sqrt{4-x^2}}{\sin^{-1}|x|}$ $⇒4-x^2≥0$ So $x^2≤4$ so $-2≤x≤2⇒x∈[-2,2]$ so $\sin^{-1}|x|⇒1≥|x|≥0=-1≤x≤1-\{0\}$ $x∈[-1,1]-\{0\}$ So $x∈[-1, 0) ∪ (0, 1]$ |
