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-- Mathematics - Section B1
Indefinite Integration
$∫log_exdx$ is equal to :
$x(log_ex)+x+C$
$x(log_ex)-x+C$
$x-x(log_ex)+C$
$-x-x(log_ex)+C$
The correct answer is Option (2) → $x(log_ex)-x+C$
$∫\log xdx$
$=x\log x-∫∫\frac{x}{x}dx$
$x(\log x)-x+C$