$∫log_exdx$ is equal to :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $x(log_ex)-x+C$
$∫\log xdx$
$=x\log x-∫∫\frac{x}{x}dx$
$x(\log x)-x+C$
$∫log_exdx$ is equal to :
Correct answer: option 2
The correct answer is Option (2) → $x(log_ex)-x+C$
$∫\log xdx$
$=x\log x-∫∫\frac{x}{x}dx$
$x(\log x)-x+C$