Three vessels whose capacities are 3 : 2 : 1 are completely filled with milk and water. The ratio of milk and water in these vessels are 5 : 2, 4 : 1 and 4 : 1 respectively. Taking \(\frac{1}{3}\) of first, \(\frac{1}{2}\) of second and \(\frac{1}{7}\) of the third mixture, a new mixture kept in a new vesselis prepared. The percentage of water in the new mixture is:

24

          Milk    :    Water   :    Total

1st :    5      :        2       :      7      ) × 5 × 3 × \(\frac{1}{3}\)

2nd:    4      :        1       :      5      ) × 7 × 2 × \(\frac{1}{2}\)

3rd:     4      :        1       :      5      ) × 7 × 1 × \(\frac{1}{7}\)

⇒       Milk     :    Water

1st :    25     :        10

2nd:    28     :        7

3rd:     4       :        1    

Total :  57     :       18    =   75 (Total)

Water Percentage = \(\frac{18}{75}\) × 100 = 24%