Three vessels whose capacities are 3 : 2 : 1 are completely filled with milk and water. The ratio of milk and water in these vessels are 5 : 2, 4 : 1 and 4 : 1 respectively. Taking \(\frac{1}{3}\) of first, \(\frac{1}{2}\) of second and \(\frac{1}{7}\) of the third mixture, a new mixture kept in a new vesselis prepared. The percentage of water in the new mixture is:
Answer & explanation
Correct answer: option 3
Milk : Water : Total
1st : 5 : 2 : 7 ) × 5 × 3 × \(\frac{1}{3}\)
2nd: 4 : 1 : 5 ) × 7 × 2 × \(\frac{1}{2}\)
3rd: 4 : 1 : 5 ) × 7 × 1 × \(\frac{1}{7}\)
⇒ Milk : Water
1st : 25 : 10
2nd: 28 : 7
3rd: 4 : 1
Total : 57 : 18 = 75 (Total)
Water Percentage = \(\frac{18}{75}\) × 100 = 24%