Practicing Success
The relation $R=\left\{(a, b): a \leq b^2\right\}$ on the set of real numbers is: |
Reflexive and symmetric Neither reflexive nor symmetric Transitive Reflexive but not symmetric |
Neither reflexive nor symmetric |
$R=\left\{(a, b): a \leq b^2\right\}$ → this is not reflexive for eg: $a=\frac{1}{2}~~~b^2=\frac{1}{4}=a^2$ here a > b → false lies R → NOT REFLEXIVE → this is not symmetric for eg: a = 2, b = 5 $a^2 = 4, ~~b^2=25$ so a ≤ b holds true b ≤ a (doesn't hold true) → Not symmetric → this is not transitive e.g: a = 2, b = -2, c = -1 $a^2 = 4, ~~b^2=4,~~c^2=1$ $a \leq b^2 \Rightarrow(a, b) \in R$ $b \leq c^2 \Rightarrow(b, c) \in R$ but $a>c \Rightarrow(a, c) \notin R$ → Not transitive Option → 2 - Neither reflexive nor symmetric |