Rohan and Ritika start running simultaneously from point X and Y towards each other. Ritika’s speed is 6/5th of Rohan’s speed. If after crossing Rohan, Ritika takes 1 hour 15 min to reach X, how much time does Rohan takes to reach Y after crossing Ritika ?
Answer & explanation
Correct answer: option 3
Ritika : Rohan
Speed ratio: 6 : 5
Ratio of distance covered before meeting: 6 : 5
Let total distance be 11 km.
For ritika after meeting,
Distance = 5 km, time = 1.25 hours. So, speed =\(\frac{5}{1.25}\) = 4 km/h
Speed of rohan = 4 × \(\frac{5}{6}\) = \(\frac{10}{3}\) km/h
Time taken by rohan to reach Y after meeting = \(\frac{6 \;× \;3}{10}\)= 1.8 = 1 hours 48 mins