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Home Questions 6AJ6F9RXS8
Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Time, Speed and Distance

Question:

Rohan and Ritika start running simultaneously from point X and Y towards each other. Ritika’s speed is 6/5th of Rohan’s speed. If after crossing Rohan, Ritika takes 1 hour 15 min to reach X, how much time does Rohan takes to reach Y after crossing Ritika ?

Options:

2 hr 12 min

2 hr 20 min

1 hr 48 min

2 hr 30 min

Correct Answer:

1 hr 48 min

Explanation:
                                                                   Ritika  :   Rohan
                                              Speed ratio:       6   :    5

Ratio of distance covered before meeting:      6   :    5

Let total distance be 11 km.
 
For ritika after meeting,
 
Distance = 5 km, time = 1.25 hours. So, speed =\(\frac{5}{1.25}\) = 4 km/h

Speed of rohan =  4 ×  \(\frac{5}{6}\) = \(\frac{10}{3}\) km/h

Time taken by rohan to reach Y after meeting = \(\frac{6  \;×  \;3}{10}\)= 1.8 = 1 hours 48 mins

CUET Questions