Match List-I compounds with their structures in List-II.
| LIST-I (Name of the compound) | LIST-II (Structure) | ||
| A. | Acetophenone | I. |  |
| B. | Vanillin | II. |  |
| C. | Salicylaldehyde | III. |  |
| D. | Cinnamaldehyde | IV. |  |
Choose the correct answer from the options given below
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A - IV, B - III, C - II, D - I
Each compound can be identified from its functional groups:
A. Acetophenone — This matches structure IV. A benzene ring joined to a –\( \ce{COCH3} \) group (a methyl phenyl ketone), \( \ce{C6H5COCH3} \).
B. Vanillin — This matches structure III. 4-Hydroxy-3-methoxybenzaldehyde: a –CHO group, with –OH para to it and –\( \ce{OCH3} \) next to the –OH. It gives vanilla its flavour.
C. Salicylaldehyde — This matches structure II. 2-Hydroxybenzaldehyde: –OH and –CHO on adjacent carbons. It is the product of the Reimer–Tiemann reaction.
D. Cinnamaldehyde — This matches structure I. 3-Phenylprop-2-enal, \( \ce{C6H5CH=CH-CHO} \). It gives cinnamon its flavour.
Shortcut: The pair A–IV appears in Options (1) and (2), and B–III then leaves only Option (1).