The correct ascending order of the following quantities in 14 gm of 6C14 atom:
(A) numbers of atoms
(B) numbers of protons
(C) number of neutrons
(D) number of nucleons
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A), (B), (C), (D)
14 g of carbon-14 is one mole, so it contains Avogadro’s number \( N_A \) of atoms. Each 6C14 nucleus has Z = 6 protons and A − Z = 8 neutrons, that is, A = 14 nucleons.
\( \text{(A) numbers of atoms} = N_A \)
\( \text{(B) numbers of protons} = 6N_A \)
\( \text{(C) number of neutrons} = 8N_A \)
\( \text{(D) number of nucleons} = 14N_A \)
So the ascending order is (A), (B), (C), (D).