A block B is pushed momentarily along a horizontal surface with an initial velocity V. If \(\mu\) is the coefficient of sliding friction between B and the surface, block B will come to rest after a time : |
\(\frac{g \mu}{V}\) \(\frac{g}{V}\) \(\frac{V}{g}\) \(\frac{V}{g\mu}\) |
\(\frac{V}{g\mu}\) |
Friction is the retarding force for the block F = ma = \(\mu\)R = \(\mu\)mg Therefore, from the first equation of motion : v = u – at 0 = v - \(\mu\)g x t ⇒ \(\frac{v}{\mu g} = t\) |