The distance b/w two railway stations is 1176 km. To cover this distance, an express train takes 10 hours less than a passenger train. While the avg. speed of the passenger train is 35 km/h less than that of express train. The time taken by passenger train to complete the travel is:
Answer & explanation
Correct answer: option 1
Time = t,
ATQ,
Speed of express = \(\frac{1176}{t - 10}\)
Speed of passenger = \(\frac{1176}{t}\)
\(\frac{1176}{t - 10}\) - \(\frac{1176}{t}\) = difference of speeds
\(\frac{1176}{t - 10}\) - \(\frac{1176}{t}\) = 35 km/h
1176t - 1176t + 11760 = 35t (t - 10)
11760 = 35t (t - 10)
336 = t (t - 10)
On solving it t = 24