Match List-I with List-II
Choose the correct answer from the options given below. |
(A)-(III), (B)-(I), (C)-(II), (D)-(IV) (A)-(II), (B)-(I), (C)-(III), (D)-(IV) (A)-(III), (B)-(I), (C)-(IV), (D)-(II) (A)-(III), (B)-(II), (C)-(I), (D)-(IV) |
(A)-(III), (B)-(I), (C)-(II), (D)-(IV) |
The correct answer is Option (1) → (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
(A) $S_N1$ Reaction: This reaction proceeds via a planar carbocation intermediate. Nucleophilic attack can occur from either side of this plane with equal probability, leading to the formation of a mixture of both enantiomers. This process is known as racemisation.
(B) Bromination of alkenes: When an alkene reacts with $Br_2$ (usually in $CCl_4$), the bromine atoms add across the double bond to adjacent carbon atoms. This produces a vicinal dibromide (or vic-dibromide).
(C) Alkylidene halides: In organic nomenclature, alkylidene halides are compounds where two halogen atoms are attached to the same carbon atom. These are also known as geminal dihalides (or gem-dihalides).
(D) Elimination of HX from alkyl halide: Dehydrohalogenation (an E1 or E2 reaction) often follows the Saytzeff (Zaitsev) rule,which states that in any dehydrohalogenation reaction, the select product is the alkene having a large number of the alkyl groups attached to the doubly bonded carbon atoms in the reaction
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