Practicing Success
According to Bohr's theory the moment of momentum of an electron revolving in second orbit of hydrogen atom will be |
2πh πh $\frac{h}{π}$ $\frac{2h}{π}$ |
$\frac{h}{π}$ |
Angular momentum $L=n\left(\frac{h}{2 \pi}\right)$ For this case n = 2, hence $L=2 \times \frac{h}{2 \pi}=\frac{h}{\pi}$ |