CUET Preparation Today
UV radiation of 6.2 eV falls on aluminium surface of work function 4.2 eV. The stopping potential for the surface is: |
10.4 V 2 V 1.5 V 4.2 V |
2 V |
The correct answer is Option (2) → 2 V Using Photoelectric equation, $eV_s=K.E.max=E_{photon}-\phi$ $⇒eV_s=6.2-4.2$ $⇒eV_s=2eV$ $⇒V_s=\frac{2}{e}=\frac{2}{1}=2V$ |
