A \( 600\ \mathrm{pF} \) capacitor is charged by a \( 100\ \mathrm{V} \) battery. The electrostatic energy stored in the capacitor is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \( 3\times10^{-6} \) J.
The energy stored in a capacitor charged to a potential difference V is
\( \displaystyle U = \frac{1}{2}CV^{2} \)
Converting the capacitance to farads:
\( C = 600\ \mathrm{pF} = 600\times10^{-12}\ \mathrm{F} = 6\times10^{-10}\ \mathrm{F} \)
\( \displaystyle U = \frac{1}{2} \times (6\times10^{-10}\ \mathrm{F}) \times (100\ \mathrm{V})^{2} \)
\( U = 3\times10^{-6}\ \mathrm{J} \)