A uniform wire of resistance \( 50\ \Omega \) is cut into \( 5 \) equal parts. These parts are now connected in parallel. The equivalent resistance of the combination is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → \( 2\ \Omega \)
Resistance is proportional to length, so each of the five equal parts has one-fifth of the total resistance. For n equal resistors in parallel, the equivalent resistance is 1/n of one of them.
\( R_{\mathrm{part}} = 50\ \Omega/5 = 10\ \Omega \)
\( R_{\mathrm{eq}} = 10\ \Omega/5 = 2\ \Omega \)
Shortcut: A wire of resistance R cut into n equal parts joined in parallel gives \( R/n^{2} = 50/25 = 2\ \Omega \).