Two unbiased coins are tossed:
Match the List-I and List-II
| List-I | List-II | ||
|---|---|---|---|
| (A) | Probability of getting one head | (I) | 3/4 |
| (B) | Probability of getting two heads | (II) | 1/2 |
| (C) | Probability of getting at most one head | (III) | 1/4 |
| (D) | Probability of getting three heads | (IV) | 0 |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
Two coins give four equally likely outcomes: HH, HT, TH, TT. Each probability is the number of favourable outcomes divided by 4.
(A) Probability of getting one head — this matches (II) 1/2. One head with one tail occurs in HT and TH: \(\frac{2}{4}=\frac{1}{2}\).
(B) Probability of getting two heads — this matches (III) 1/4. Only HH has two heads: \(\frac{1}{4}\).
(C) Probability of getting at most one head — this matches (I) 3/4. “At most one” means no head or one head: HT, TH and TT, so \(\frac{3}{4}\).
(D) Probability of getting three heads — this matches (IV) 0. Two coins cannot show three heads, so it is an impossible event.