Practicing Success
Practicing Success
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Let $I=\int\limits_a^b(x^4 -2x^2) dx$. The ordered pair (a, b) for which I attains the least value, is |
$(0,\sqrt{2})$ $(\sqrt{2},-\sqrt{2})$ $(-\sqrt{2},2)$ $(-\sqrt{2},0)$ |
$(-\sqrt{2},2)$ |
Clearly, the absolute value of I represents the area bounded by the curve $y = x^4 -2x^2$ and x-axis. So, the value of I is least when $a=-\sqrt{2}$ and $b = \sqrt{2}$.
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