Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If \(\frac{a}{4}\) = \(\frac{b}{3}\) = \(\frac{c}{2}\)

then find (\(\frac{a + b }{a + b + c }\)).

Options:

\(\frac{4}{9}\)

\(\frac{7}{9}\)

\(\frac{7}{19}\)

\(\frac{2}{9}\)

Correct Answer:

\(\frac{7}{9}\)

Explanation:

Given, \(\frac{a}{4}\) = \(\frac{b}{3}\) = \(\frac{c}{2}\)

Here we can directly conclude that 

a = 4, b = 3, c = 2, hence

⇒ (\(\frac{a + b }{a + b + c }\)) = (\(\frac{4 + 3 }{4 + 3 + 2}\)) \(\frac{7}{9}\)