If $\frac{x}{8}+\frac{8}{x}=1$, then the value of x3 is:

-256 -512 256 512

-512

If we have x + \(\frac{1}{x}\) = 1 Then x3 = -1 always  So we have  = $\frac{x}{8}+\frac{8}{x}=1$ Then \(\frac{x}{8^3}\) = -1 x3 = -512