\(\int \frac{x^2}{1+x^2}dx=\)

\(x+\tan^{-1}x+c\) \(x^2+\tan^{-1}x+c\) \(x-\tan^{-1}x+c\) \(x^2-\tan^{-1}x+c\)

\(x-\tan^{-1}x+c\)

\(\frac{x^2}{1+x^2}=1-\frac{1}{1+x^2}\)