Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The wavelength of Lyman series is

Options:

$\frac{4}{3 × 10967}$ cm

$\frac{3}{4 × 10967}$ cm

$\frac{4 × 10967}{3}$ cm

$\frac{3}{4} × 10967$ cm

Correct Answer:

$\frac{4}{3 × 10967}$ cm

Explanation:

$\frac{1}{\lambda}=R_H\left[\frac{1}{n_1^2}-\frac{1}{n_2^2}\right]$. For Lyman series $n_1=1$ and $n_2=2,3,4$, When $n_2=2$, we get $\lambda=\frac{4}{3 R_H}=\frac{4}{3 \times 10967}$ cm